find_vertex() not works
I'm trying to retrieve all the nodes of a graph that belong to a specific type. I use the find_vertex for this: referents = find_vertex(graph, graph.vertex_properties['type'], 'referent') But all I get is this error: File "/usr/lib/python2.7/dist-packages/graph_tool/util/__init__.py", line 58, in find_vertex (val, val)) TypeError: No registered converter was able to extract a C++ reference to type graph_tool::GraphInterface from this Python object of type Graph. Any clue of what is the problem? -- View this message in context: http://main-discussion-list-for-the-graph-tool-project.982480.n3.nabble.com/... Sent from the Main discussion list for the graph-tool project mailing list archive at Nabble.com.
On 07/09/2012 12:13 PM, josubg wrote:
I'm trying to retrieve all the nodes of a graph that belong to a specific type. I use the find_vertex for this:
referents = find_vertex(graph, graph.vertex_properties['type'], 'referent')
But all I get is this error:
File "/usr/lib/python2.7/dist-packages/graph_tool/util/__init__.py", line 58, in find_vertex (val, val)) TypeError: No registered converter was able to extract a C++ reference to type graph_tool::GraphInterface from this Python object of type Graph.
Any clue of what is the problem?
This is a bug. I have fixed it now in the git version. Cheers, Tiago -- Tiago de Paula Peixoto <tiago@skewed.de>
I can't clone your main repo. I cloned the github ones but ins't updated with the new changes. The gitorious ones also is outdated. thanks for the quick fix! -- View this message in context: http://main-discussion-list-for-the-graph-tool-project.982480.n3.nabble.com/... Sent from the Main discussion list for the graph-tool project mailing list archive at Nabble.com.
Thanks a Lot! On Wed, Jul 11, 2012 at 10:41 AM, Tiago de Paula Peixoto <tiago@skewed.de>wrote:
On 07/11/2012 10:22 AM, josubg wrote:
I can't clone your main repo. I cloned the github ones but ins't updated with the new changes. The gitorious ones also is outdated.
I've updated the github and gitorious repos.
Cheers, Tiago
-- Tiago de Paula Peixoto <tiago@skewed.de>
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